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单位球面中Clifford环面的刚性定理*

时间:2024-08-31

胡传峰, 姬 秀

(长江大学 文理学院, 湖北 荆州 434000)

单位球面中Clifford环面的刚性定理*

胡传峰, 姬 秀

(长江大学 文理学院, 湖北 荆州 434000)

主曲率; 数量曲率; Clifford环

0 引 言

1 预备知识

设Mn是单位球面Sn+1(1)中的紧致极小超曲面, 在Sn+1中选取标准正交标架场e1,…,en+1, 使得限制于Mn时,e1,…,en与Mn相切. 令w1,…,wn+1是上述标架的对偶标架, 并约定各类指标范围为

1≤A,B,C…≤n+1, 1≤i,j,k…≤n.

在Sn+1(1)上, 结构方程为

KABCD=δACδBD-δADδBC.

限制于Mn时,

wn+1=0,wn+1i=hijwj,hij=hji,

由式(2)得

用hijk及hijkl分别表示hij的一阶, 二阶共变导数, 则有

进而有如下Codazzi方程和Ricci恒等式

定义hij的Laplace为

2 主要定理及证明

证明为方便起见, 用g表示gj.

充分性: 设βij=0,i=1,…,n, 则由已知条件可得gj=n.

证毕.

证明选取适当的标架, 使得hij=λiδij, 且设λn<0<λ1≤λ2≤…≤λn-1, 定义

则有

由S为常数可得

由式(11), 式(13)和式(14)及等式

可得

SΔF=

将等式

代入式(15)得

SΔF=

即第三项也非正. 接下来, 证明第四项也非正.

n.

定义βij=hiij, 则λi,βij满足定理1的条件. 若固定j∈{1,…,n-1}, 则由定理1得到|hnnj|≠max{|hiij|,i=1,…,n} 或者hnnj=0. 用gj∈In-1={1,…,n-1} 表示使得等式|hgjgjj|=max{|hiij|,i=1,…,n} 成立的指标. 考虑In-1的子集A={j∈In-1;gj=j},B={j∈In-1;gj≠j,n},C={j∈In-1;gj=n}. 不失一般性可令A={1,…,r},B={r+1,…,t},C={t+1,…,n-1}. 这里我们约定若A为空集, 则r=0; 若B为空集, 则t=r; 若C为空集, 则t=n-1. 比如若B为空集, 则A={1,…,r},C={r+1,…,n-1}.

下面我们用更简单的方式记

(n-S).

因此有

由Mn紧致可得

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RigidityTheoremofCliffordTorusinaUnitSphere

HU Chuan-feng, JI Xiu

(College of Arts and Science, Yangtze University, Jingzhou 434000, China)

principal curvature; scalar curvature; Clifford torus

1673-3193(2017)03-0260-04

2016-09-06

湖北省教育厅科学技术研究基金资助项目(B2016453, B2016458)

胡传峰(1978-), 男, 讲师, 硕士, 主要从事微分几何的研究.

O186.12

A

10.3969/j.issn.1673-3193.2017.03.002

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